# (y + 6)(y+4) =

$$Y^{2}+10 y+24$$

Explanation

Take the variable in the first set times the first variable in the second set: $$(y) y=y^{2}$$. Then, take the first variable in the first set times the second variable in the second set: y(4) = 4y.
So far, we have: $$y^{2}+4 y$$.
Now, take the second variable in the first set times the first variable in the second set: 6(y) = 6y. Now, we have: $$y^{2}+4 y+6 y$$
Finally, we have the second variable in the first set times the second variable in the second set: $$6 \times 4 = 24$$
$$y^{2}+4 y+6 y+24=y^{2}+10 y+24$$