\( (x - 5)({x^2} + 7x + 2) = ? \)

\(x^{3}+2 x^{2}-33 x-10\)

Explanation

To solve this problem multiply each variable in the binomial with each variable in the trinomial:

\((x - 5)({x^2} + 7x + 2) = \)

\( (x \times x^2) + (x \times 7x) + (x \times 2) + (-5 \times x^2) + (-5 \times 7x) + (-5 \times 2)=\)

\( (x^3 + 7x^2 + 2x) +(-5x^2 - 35x - 10)= \)

\( x^3 + 2x^2 -33x-10 \)

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