# Which of these expressions is equivalent to: $$3 x^{3} y^{5}+3 x^{5} y^{3}-\left(4 x^{5} y^{3}-3 x^{3} y^{5}\right)$$

$$6 x^{3} y^{5}-x^{5} y^{3}$$

Explanation

The key to this problem is distributing the negative sign. When distributing a negative sign, each term has a change of sign from negative to positive or from positive to negative.
$$3 x^{3} y^{5}+3 x^{5} y^{3}-\left(4 x^{5} y^{3}-3 x^{3} y^{5}\right)$$
$$3{x^3}{y^5} + 3{x^5}{y^3} - 4{x^5}{y^3}+ 3{x^3}{y^5}$$
$$6{x^3}{y^5} - {x^5}{y^3}$$