\(\sqrt {{{(6 + x)}^2}} = \)

\(6+x\)

Explanation

This is so easy that it may tempt you to think that the correct answer is too obvious. The square root of \( {(6 + x)^2} \)is simply 6 + x.

\( (x - 5)({x^2} + 7x + 2) = ? \)

\(2(5+3 \times \sqrt{25}) \div(14-9) \times 4=?\)

\( {({6^3})^9}? \)