# Solve:$$3+6 x \leq 3 x-3$$

$$x \leq-2$$

Explanation

Subtract 3x from both sides and combine the x terms: $$3+6 x \leq 3 x-3 ; 3+3 x \leq-3$$. Subtract 3 from both sides: $$3 x \leq-3-3 ; 3 x \leq-6$$. Divide both sides by 3: $$x \leq-2$$