Solve:\(3+6 x \leq 3 x-3\)

\(x \leq-2\)

Explanation

Subtract 3x from both sides and combine the x terms: \(3+6 x \leq 3 x-3 ; 3+3 x \leq-3\). Subtract 3 from both sides: \(3 x \leq-3-3 ; 3 x \leq-6\). Divide both sides by 3: \(x \leq-2\)

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