If \(y^{4}+x^{4}=y^{4}+p^{4}\) , then x =
\(x=p\)
Explanation
To solve, subtract \(y^{4}\) from both sides of the equation and then take the fourth root:
\(y^{4}+x^{4}-y^{4}=y^{4}+p^{4}-y^{4}\) \(x^{4}=p^{4}\) x = p
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\(x \times x^{3}\)
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