If “x” = 12, what’s the value of “p” in the equation, \( p = (\frac{x^{2}} {6}) - 4 \) ?

Explanation

We know that “x” is equal to 12, therefore: \(p=\left(12^{2} / 6\right)-4=(144 / 6)-4=(24-4)=20\)

In the diagram provided what is the value of “y”?

\( {({8^5})^9} = ?\)