\(\frac{{{6^4}}}{{{6^3} \times {6^2}}} = ?\)
\(6^{-1}\)
Explanation
\(a^{m} \times a^{n}=a^{m+m}, \frac{a^{m}}{a^{n}}=a^{m-n} . \text { So } \frac{6^{4}}{6^{3} \times 6^{2}}=\frac{6^{4}}{6^{5}}=6^{4-5}=6^{-1}\)
If n is a positive integer divisible by 7, and if n < 70, what is the greatest possible value of n?
\( {\rm{2}}({\rm{5}} - \sqrt {{\rm{16}}} ) \div ({\rm{14}} - {\rm{12}}) \times {\rm{3}} = ?\)
If \((8)x^2 = 128\) , then “x” is:
Solve:\(3+6 x \leq 3 x-3\)