A 50 ft by 30 ft rectangular garden has a circular fountain in the center. If the radius of the fountain is 6 ft, what is the area of the garden outside the fountain?

1387 sq. ft

Explanation

The area of the rectangular garden including the fountain \(=\text { length } \times \text { width }=50 \mathrm{ft} \times 30 \mathrm{ft}=1500 \text { sq. ft }\). The area of the \(\text { fountain }=\pi r^{2}=\pi\left(6^{2}\right)=36 \pi=113 \text { sq. ft }\). So the area of the garden outside the fountain = 1500 – 113 = 1387 sq. ft.

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