(4x+2) (x+1) =

\(4 x^{2}+6 x+2\)

Explanation

This is a multiplying binomials problem. Multiply the first term in the first binomial by both terms in the second binomial:

\(4{x^2} + 4x \)
Then multiply the second term in the first binomial by each term in the second binomial:
2x + 2
Adding them all together you get:
\(4 x^{2}+4 x+2 x+2\)
\(4 x^{2}+6 x+2\)

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